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          ACIDS, BASES AND SALTS

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          What is the color of phenolphthalein in basic solution?

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          Baking soda is chemically known as —

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          Which of the following solutions has the highest concentration of hydrogen ions? \(H^+\)

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          Which acid is present in curd?

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          Identify the compound used in antacid tablets to relieve acidity.

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          Which of the following solutions turns blue litmus red?

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          Which of the following represents a neutralization reaction?

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          When phenolphthalein is added to a solution, it turns pink. What does this indicate about the solution?

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          Which reaction represents neutralization?

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          A solution shows \(pH = 2\). What can you infer about it?

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          When \(CO_2\) gas is passed through lime water, it first turns milky and then clear. What type of reaction occurs when the solution becomes clear again?

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          • Acids, Bases and Salts | Study

            Acids, Bases and Salts | Study


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            • Areas Related to Circles | Material

              Areas Related to Circles | Material


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              • BASIC GEOMETRICAL IDEAS | Study

                BASIC GEOMETRICAL IDEAS | Study


                Pre-Requisires

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                • Basics of Geometry | Notes

                  1. Introduction to Geometry

                  • Geometry is the branch of mathematics that deals with shapes, sizes, relative positions of figures, and properties of space.

                  • The word Geometry comes from Greek words: Geo = Earth and Metron = Measurement.


                  2. Fundamental Terms

                  2.1 Point

                  • A point is a precise location in space.

                  • It has no length, breadth, or thickness.

                  • Notation: Usually denoted by a capital letter, e.g., A,B,CA, B, C.

                  2.2 Line

                  • A line is a straight path of points extending infinitely in both directions.

                  • Notation: Line passing through points AA and BB is written as ABAB or AB\overleftrightarrow{AB}.

                  2.3 Line Segment

                  • A line segment is part of a line with two endpoints.

                  • Notation: Line segment joining points AA and BB is AB\overline{AB}.

                  2.4 Ray

                  • A ray starts at one point and extends infinitely in one direction.

                  • Notation: Ray starting at AA passing through BB is AB\overrightarrow{AB}.

                  2.5 Plane

                  • A plane is a flat surface that extends infinitely in all directions.

                  • Represented by a quadrilateral figure in diagrams.


                  3. Angle And Its Types

                  • An angle is formed by two rays with a common endpoint called the vertex.

                  3.1 Classification

                  1. Acute Angle: 0<θ<900^\circ < \theta < 90^\circ

                  2. Right Angle: θ=90\theta = 90^\circ

                  3. Obtuse Angle: 90<θ<18090^\circ < \theta < 180^\circ

                  4. Straight Angle: θ=180\theta = 180^\circ

                  5. Reflex Angle: 180<θ<360180^\circ < \theta < 360^\circ

                  Formula:

                  Sum of angles on a straight line=180\text{Sum of angles on a straight line} = 180^\circSum of angles around a point=360\text{Sum of angles around a point} = 360^\circ


                  4. Triangle And Its Types

                  • A triangle has 3 sides and 3 angles.

                  4.1 Based on Sides

                  1. Equilateral: All sides equal

                  2. Isosceles: Two sides equal

                  3. Scalene: All sides unequal

                  4.2 Based on Angles

                  1. Acute-angled: All angles < 9090^\circ

                  2. Right-angled: One angle = 9090^\circ

                  3. Obtuse-angled: One angle > 9090^\circ

                  Important Property (Triangle Sum Theorem):

                  Sum of angles in a triangle=180\text{Sum of angles in a triangle} = 180^\circ

                  5. Quadrilateral And Its Types

                  • A quadrilateral has 4 sides and 4 angles.

                  5.1 Types

                  1. Square: All sides equal, all angles 9090^\circ

                  2. Rectangle: Opposite sides equal, all angles 9090^\circ

                  3. Parallelogram: Opposite sides parallel and equal

                  4. Rhombus: All sides equal, opposite angles equal

                  5. Trapezium: One pair of opposite sides parallel

                  Property: Sum of angles in a quadrilateral:

                  Sum of angles=360\text{Sum of angles} = 360^\circ

                  6. Circles And Its Parts.

                  • A circle is a set of points equidistant from a fixed point called the centre.

                  • Radius (r): Distance from centre to any point on the circle

                  • Diameter (d): Twice the radius, d=2rd = 2r

                  • Circumference (C): C=2πrC = 2 \pi r

                  • Area (A): A=πr2A = \pi r^2


                  7. Basic Geometrical Constructions

                  1. Constructing a bisector of a line segment

                  2. Constructing an angle bisector

                  3. Constructing perpendiculars from a point on a line or outside a line

                  4. Constructing triangles using SSS, SAS, ASA, RHS criteria


                  8. Important Theorems

                  1. Pythagoras Theorem:

                  In a right triangle: AB2+BC2=AC2\text{In a right triangle: } AB^2 + BC^2 = AC^2

                  1. Triangle Sum Theorem:

                  A+B+C=180\angle A + \angle B + \angle C = 180^\circ

                  1. Exterior Angle Theorem:

                  Exterior angle of a triangle=Sum of the two opposite interior angles\text{Exterior angle of a triangle} = \text{Sum of the two opposite interior angles}

                  9. Tips & Tricks

                  • Always label points clearly in diagrams.

                  • Use a protractor for accurate angle measurement.

                  • Remember the sum of angles for triangle = 180°, quadrilateral = 360°.

                  • Practice constructing triangles using different combinations of sides and angles.


                  Diagram Placeholders:

                  • [Point, Line, Line Segment, Ray]

                  • [Triangle with labeled angles]

                  • [Quadrilateral types]

                  • [Circle with radius and diameter]

                  Worksheet on Basics of Geometry (Math Olympiad Preparation)

                  Topic: Basics of Geometry
                  Class: 6–9 (CBSE & Olympiad Level)
                  Marks: Practice Worksheet
                  Time: 45–60 minutes


                  Section A — Very Short Answer Questions (1 Mark Each)

                  (Concept Recall & Definitions)

                  1. Define a point and a line in geometry.

                  2. How many endpoints does a line segment have?

                  3. What is the measure of a straight angle?

                  4. Name the instrument used to draw circles.

                  5. Write the sum of all angles around a point.

                  6. How many vertices does a triangle have?

                  7. What is the sum of the angles of a quadrilateral?

                  8. Which type of angle is greater than 180° but less than 360°?

                  9. Write the relationship between radius and diameter.

                  10. Give one example of a real-life object in the shape of a circle.


                  Section B — Short Answer Questions (2 Marks Each)

                  (Understanding & Application)

                  1. Draw and name the following:
                     (a) Line segment
                     (b) Ray
                     (c) Line

                  2. If one angle of a triangle is 9090^\circ and another is 4545^\circ, find the third angle.

                  3. The sum of two angles is 130130^\circ. Find the measure of their supplementary angles.

                  4. In a quadrilateral, three angles are 80,90,7580^\circ, 90^\circ, 75^\circ. Find the fourth angle.

                  5. A circle has a radius of 7 cm. Find its circumference using π=227\pi = \frac{22}{7}.
                    C=2πr=2×227×7=?


                  Section C — Application / Reasoning (3 Marks Each)

                  1. The sum of two adjacent angles on a straight line is always 180180^\circ. Prove this statement using a neat diagram.

                  2. A triangle has sides 6 cm, 8 cm, and 10 cm. Verify whether it is a right-angled triangle using the Pythagoras Theorem.
                    a2+b2=c2a^2 + b^2 = c^2

                  3. In a circle with diameter 14 cm, find:
                     (a) Radius
                     (b) Circumference
                     (c) Area
                     Use π=227\pi = \frac{22}{7}.

                  4. The exterior angle of a triangle is 120120^\circ and one of the interior opposite angles is 4040^\circ.
                     Find the other interior opposite angle.

                  5. In parallelogram ABCD, A=70\angle A = 70^\circ. Find all other angles.
                     (Hint: Opposite angles are equal and adjacent angles are supplementary.)


                  Section D — Higher Order Thinking (HOTS) Questions (4–5 Marks Each)

                  1. A triangle has two equal angles and the third angle is 9696^\circ.
                     Find each of the equal angles and name the triangle.

                  2. The sum of the interior angles of an nn-sided polygon is 14401440^\circ.
                     Find the value of nn.

                  3. Draw a circle of radius 4 cm, mark points:
                     (a) Inside the circle
                     (b) On the circle
                     (c) Outside the circle

                  4. A quadrilateral has three angles measuring 110,95,70110^\circ, 95^\circ, 70^\circ. Find the fourth angle and classify the quadrilateral.

                  5. A line segment AB=8 cmAB = 8 \text{ cm} is bisected at MM.
                     Find AMAM and MBMB, and justify your answer using geometric reasoning.


                  Section E — Multiple Choice Questions (MCQs)

                  (For Quick Revision)

                  1. The total number of right angles in a rectangle is:
                     A. 1 B. 2 C. 3 D. 4

                  2. The angle formed by two perpendicular lines is:
                     A. Acute B. Right C. Obtuse D. Straight

                  3. The sum of all angles in a triangle is: 
                     A. 9090^\circ B. 180180^\circ C. 270270^\circ D. 360360^\circ

                  4. A line segment joining the centre of a circle to a point on its circumference is called:
                     A. Chord B. Diameter C. Radius D. Tangent

                  5. Which of the following statements is false?
                     A. Every square is a rectangle.
                     B. Every rectangle is a square.
                     C. Every square is a rhombus.
                     D. Every rhombus is a parallelogram.

                  Worksheet Hints, Solutions & Answers


                  Section A – Very Short Answer (1 Mark Each)

                  Q1. Define a point and a line.

                  Hint: Recall definitions from basic geometry.
                  Solution:

                  • A point has position but no size.

                  • A line extends endlessly in both directions, made of infinite points.
                    Answer: Point – no dimensions; Line – extends infinitely both ways.


                  Q2. How many endpoints does a line segment have?

                  Hint: Think of a line with fixed ends.
                  Solution: A line segment has two endpoints.
                  Answer: 2 endpoints.


                  Q3. Measure of a straight angle?

                  Hint: It lies on a straight line.
                  Solution: 180180^\circ.
                  Answer: 180180^\circ


                  Q4. Instrument to draw circles?

                  Hint: Used with pencil and pin.
                  Answer: Compass.


                  Q5. Sum of all angles around a point?

                  Solution:

                  Sum of all angles around a point=360\text{Sum of all angles around a point} = 360^\circ

                  Answer: 360360^\circ


                  Q6. Vertices of a triangle?

                  Answer: 3 vertices.


                  Q7. Sum of angles of a quadrilateral?

                  Solution:

                  Sum=360\text{Sum} = 360^\circ

                  Answer: 360360^\circ


                  Q8. Type of angle greater than 180° but less than 360°?

                  Answer: Reflex angle.


                  Q9. Relationship between radius (r) and diameter (d)?

                  d=2rd = 2rAnswer: Diameter = 2 × Radius.

                  Q10. Example of circle shape?

                  Answer: Clock, coin, wheel.


                  Section B – Short Answer (2 Marks Each)

                  Q11. Draw and name: line segment, ray, line.

                  Hint: Use ruler and pencil.
                  Solution:

                  • AB\overline{AB} → line segment

                  • AB\overrightarrow{AB} → ray

                  • AB\overleftrightarrow{AB} → line
                    Answer: As shown by symbols above.


                  Q12. Triangle with angles 90° and 45° → find third.

                  Solution:

                  Sum=18090+45+x=180x=45

                  Answer: Third angle = 4545^\circ.


                  Q13. Two angles sum 130° → find supplementary angles.

                  Hint: Supplementary ⇒ sum 180°.
                  Solution:

                  180130=50180 – 130 = 50

                  Answer: 5050^\circ.


                  Q14. Quadrilateral angles 80°, 90°, 75° → fourth?

                  80+90+75+x=360

                  x=11580 + 90 + 75 + x = 360 \Rightarrow x = 115Answer: Fourth angle = 115115^\circ.


                  Q15. Circle radius 7 cm → circumference.

                  C=2πr=2×227×7=44C = 2\pi r = 2 \times \frac{22}{7} \times 7 = 44Answer: C=44 cmC = 44\ \text{cm}.


                  Section C – Application (3 Marks Each)

                  Q16. Prove: Adjacent angles on a straight line = 180°.

                  Hint: Angles on straight line form linear pair.
                  Solution:
                  Let ∠1 + ∠2 form straight line.
                  By linear-pair axiom:

                  1+2=180\angle1 + \angle2 = 180^\circ

                  Answer: Hence proved.


                  Q17. Triangle sides 6 cm, 8 cm, 10 cm → right triangle?

                  62+82=36+64=100=1026^2 + 8^2 = 36 + 64 = 100 = 10^2

                  Answer: Yes, right-angled at side 6 and 8 cm.


                  Q18. Circle diameter 14 cm → radius, C, A.

                  r=7,C=2πr=44,A=πr2=227×7×7=154r = 7,\quad C = 2\pi r = 44,\quad A = \pi r^2 = \frac{22}{7}\times7\times7 = 154Answer: Radius 7 cm, Circumference 44 cm, Area 154 cm².


                  Q19. Exterior angle 120°, interior opposite 40° → other?

                  120=40+xx=80120 = 40 + x \Rightarrow x = 80

                  Answer: 8080^\circ.

                  Q20. In parallelogram ABCD, ∠A = 70° → others?

                  A=C=70,B=D=110\angle A = \angle C = 70,\quad \angle B = \angle D = 110

                  Answer: 70°, 110°, 70°, 110°.


                  Section D – HOTS (4–5 Marks Each)

                  Q21. Two equal angles, third 96°.

                  x+x+96=1802x=84x=42x + x + 96 = 180 \Rightarrow 2x = 84 \Rightarrow x = 42

                  Answer: Equal angles = 42° each; Isosceles triangle.


                  Q22. Sum of interior angles = 1440°.

                  Formula → (n2)×180=1440(n-2) × 180 = 1440

                  n2=8n=10n-2 = 8 \Rightarrow n = 10

                  Answer: 10-sided polygon (decagon).


                  Q23. Circle radius 4 cm → mark points.

                  Hint: Use compass radius 4 cm.
                  Answer: One inside, one on, one outside — as constructed.


                  Q24. Quadrilateral angles 110°, 95°, 70° → fourth?

                  110+95+70+x=360x=85110 + 95 + 70 + x = 360 \Rightarrow x = 85

                  Answer: Fourth angle = 85°; Irregular quadrilateral.


                  Q25. AB=8AB = 8 cm bisected at M.AM=MB=82=4AM = MB = \frac{8}{2} = 4

                  Answer: AM = MB = 4 cm; M is midpoint.


                  Section E – MCQs

                  No.QuestionAnswer
                  26Right angles in rectangleD – 4
                  27Angle between perpendicular linesB – Right angle
                  28Sum of triangle anglesB – 180°
                  29Centre to circumference lineC – Radius
                  30False statementB – Every rectangle is a square

                  Bonus Challenge – Clock Problem

                  At 3:00 the clock hands are at a right angle (90°). Find the next time between 3:00 and 4:00 when they again form a 90° angle.


                  1) Write angles of hour and minute hands (in degrees) at time 3:t3{:}t minutes

                  • Hour hand: at 3:00 it is at 9090^\circ. It moves 0.50.5^\circ per minute, so at tt minutes past 3:

                  Hour angle=90+0.5t\text{Hour angle} = 90 + 0.5t

                  • Minute hand: moves 66^\circper minute, so at tt minutes:

                  Minute angle=6t\text{Minute angle} = 6t

                  2) Angle between the hands

                  The (smaller) angle between them is the absolute difference:

                  Angle=6t(90+0.5t)=112t90\text{Angle} = \big|6t – (90 + 0.5t)\big| = \left|\frac{11}{2}t – 90\right|(we used 6t0.5t=5.5t=112t6t – 0.5t = 5.5t = \tfrac{11}{2}t).

                  3) Set the angle equal to 9090^\circ and solve

                  We need

                  112t90=90.\left|\frac{11}{2}t – 90\right| = 90.

                  This gives two cases.

                  Case A: 112t90=90\dfrac{11}{2}t – 90 = 90

                  • Add 9090 to both sides:

                    112t=180.\dfrac{11}{2}t = 180.

                  • Multiply both sides by 22:

                    11t=360.11t = 360.

                  • Divide by 1111. Do the division digit-by-digit:

                    t=36011.t = \frac{360}{11}.

                    Long division: 1111 goes into 360360 exactly 3232 times (because 11×32=35211\times32=352), remainder 360352=8360-352=8.
                    So

                    t=32  811 minutes.

                  • Convert the fractional minute 811\dfrac{8}{11} to seconds:

                    811×60=48011 seconds.\frac{8}{11}\times 60 = \frac{480}{11}\ \text{seconds}.

                    Divide 480480 by 1111 : 11×43=47311\times43=473, remainder 480473=7480-473=7.
                    So 48011=43  711\dfrac{480}{11}=43\;\frac{7}{11} seconds.

                    Therefore

                    t=32 minutes  43  711 seconds.t = 32\ \text{minutes}\;43\;\frac{7}{11}\ \text{seconds}.

                    As a decimal, 711\dfrac{7}{11} second 0.63636\approx 0.63636 s, so

                    t32 minutes 43.636 seconds.

                  Case B: 112t90=90\dfrac{11}{2}t – 90 = -90

                  • Add 9090 to both sides:

                    112t=0t=0.

                  This is the starting time 3:003{:}00 (the initial right angle).

                  We want the next time after 3:00, so we take the positive solution from Case A.


                  Final answer (exact and approximate)

                  • Exact: t=36011t = \dfrac{360}{11} minutes after 3:00, i.e. 3:32 ⁣: ⁣43 7113{:}32\!:\!43\ \dfrac{7}{11} seconds.

                  • Approximate: 3:32:43.636… (3 hours, 32 minutes, 43.636 seconds).

                  So the hands next form a right angle at about 3:32:43.64.

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