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1. Introduction to Geometry

  • Geometry is the branch of mathematics that deals with shapes, sizes, relative positions of figures, and properties of space.

  • The word Geometry comes from Greek words: Geo = Earth and Metron = Measurement.


2. Fundamental Terms

2.1 Point

  • A point is a precise location in space.

  • It has no length, breadth, or thickness.

  • Notation: Usually denoted by a capital letter, e.g., A,B,CA, B, C.

2.2 Line

  • A line is a straight path of points extending infinitely in both directions.

  • Notation: Line passing through points AA and BB is written as ABABΒ or AB↔\overleftrightarrow{AB}.

2.3 Line Segment

  • A line segment is part of a line with two endpoints.

  • Notation: Line segment joining points AA and BB is ABβ€Ύ\overline{AB}.

2.4 Ray

  • A ray starts at one point and extends infinitely in one direction.

  • Notation: Ray starting at AA passing through BB is ABβ†’\overrightarrow{AB}.

2.5 Plane

  • A plane is a flat surface that extends infinitely in all directions.

  • Represented by a quadrilateral figure in diagrams.


3. Angle And Its Types

  • An angle is formed by two rays with a common endpoint called the vertex.

3.1 Classification

  1. Acute Angle: 0∘<θ<90∘0^\circ < \theta < 90^\circ

  2. Right Angle: θ=90∘\theta = 90^\circ

  3. Obtuse Angle: 90∘<θ<180∘90^\circ < \theta < 180^\circ

  4. Straight Angle: θ=180∘\theta = 180^\circ

  5. Reflex Angle: 180∘<θ<360∘180^\circ < \theta < 360^\circ

Formula:

Sum of angles on a straight line=180∘\text{Sum of angles on a straight line} = 180^\circSum of angles around a point=360∘\text{Sum of angles around a point} = 360^\circ


4. Triangle And Its Types

  • A triangle has 3 sides and 3 angles.

4.1 Based on Sides

  1. Equilateral: All sides equal

  2. Isosceles: Two sides equal

  3. Scalene: All sides unequal

4.2 Based on Angles

  1. Acute-angled: All angles < 90∘90^\circ

  2. Right-angled: One angle = 90∘90^\circ

  3. Obtuse-angled: One angle > 90∘90^\circ

Important Property (Triangle Sum Theorem):

Sum of angles in a triangle=180∘\text{Sum of angles in a triangle} = 180^\circ

5. Quadrilateral And Its Types

  • A quadrilateral has 4 sides and 4 angles.

5.1 Types

  1. Square: All sides equal, all angles 90∘90^\circ

  2. Rectangle: Opposite sides equal, all angles 90∘90^\circ

  3. Parallelogram: Opposite sides parallel and equal

  4. Rhombus: All sides equal, opposite angles equal

  5. Trapezium: One pair of opposite sides parallel

Property: Sum of angles in a quadrilateral:

Sum of angles=360∘\text{Sum of angles} = 360^\circ

6. CirclesΒ And Its Parts.

  • A circle is a set of points equidistant from a fixed point called the centre.

  • Radius (r): Distance from centre to any point on the circle

  • Diameter (d): Twice the radius, d=2rd = 2r

  • Circumference (C): C=2Ο€rC = 2 \pi r

  • Area (A): A=Ο€r2A = \pi r^2


7. Basic Geometrical Constructions

  1. Constructing a bisector of a line segment

  2. Constructing an angle bisector

  3. Constructing perpendiculars from a point on a line or outside a line

  4. Constructing triangles using SSS, SAS, ASA, RHS criteria


8. Important Theorems

  1. Pythagoras Theorem:

InΒ aΒ rightΒ triangle:Β AB2+BC2=AC2\text{In a right triangle: } AB^2 + BC^2 = AC^2

  1. Triangle Sum Theorem:

∠A+∠B+∠C=180∘\angle A + \angle B + \angle C = 180^\circ

  1. Exterior Angle Theorem:

ExteriorΒ angleΒ ofΒ aΒ triangle=SumΒ ofΒ theΒ twoΒ oppositeΒ interiorΒ angles\text{Exterior angle of a triangle} = \text{Sum of the two opposite interior angles}

9. Tips & Tricks

  • Always label points clearly in diagrams.

  • Use a protractor for accurate angle measurement.

  • Remember the sum of angles for triangle = 180Β°, quadrilateral = 360Β°.

  • Practice constructing triangles using different combinations of sides and angles.


Diagram Placeholders:

  • [Point, Line, Line Segment, Ray]

  • [Triangle with labeled angles]

  • [Quadrilateral types]

  • [Circle with radius and diameter]

Worksheet on Basics of Geometry (Math Olympiad Preparation)

Topic: Basics of Geometry
Class: 6–9 (CBSE & Olympiad Level)
Marks: Practice Worksheet
Time: 45–60 minutes


Section A β€” Very Short Answer Questions (1 Mark Each)

(Concept Recall & Definitions)

  1. Define a point and a line in geometry.

  2. How many endpoints does a line segment have?

  3. What is the measure of a straight angle?

  4. Name the instrument used to draw circles.

  5. Write the sum of all angles around a point.

  6. How many vertices does a triangle have?

  7. What is the sum of the angles of a quadrilateral?

  8. Which type of angle is greater than 180Β° but less than 360Β°?

  9. Write the relationship between radius and diameter.

  10. Give one example of a real-life object in the shape of a circle.


Section B β€” Short Answer Questions (2 Marks Each)

(Understanding & Application)

  1. Draw and name the following:
     (a) Line segment
     (b) Ray
     (c) Line

  2. If one angle of a triangle is 90∘90^\circ and another is 45∘45^\circ, find the third angle.

  3. The sum of two angles is 130∘130^\circ. Find the measure of their supplementary angles.

  4. In a quadrilateral, three angles are 80∘,90∘,75∘80^\circ, 90^\circ, 75^\circ. Find the fourth angle.

  5. A circle has a radius of 7 cm. Find its circumference using Ο€=227\pi = \frac{22}{7}.
     C=2Ο€r=2Γ—227Γ—7=?


Section C β€” Application / Reasoning (3 Marks Each)

  1. The sum of two adjacent angles on a straight line is always 180∘180^\circ. Prove this statement using a neat diagram.

  2. A triangle has sides 6 cm, 8 cm, and 10 cm. Verify whether it is a right-angled triangle using the Pythagoras Theorem.
     a2+b2=c2a^2 + b^2 = c^2

  3. In a circle with diameter 14 cm, find:
     (a) Radius
     (b) Circumference
     (c) Area
     Use Ο€=227\pi = \frac{22}{7}.

  4. The exterior angle of a triangle is 120∘120^\circ and one of the interior opposite angles is 40∘40^\circ.
     Find the other interior opposite angle.

  5. In parallelogram ABCD, ∠A=70∘\angle A = 70^\circ. Find all other angles.
     (Hint: Opposite angles are equal and adjacent angles are supplementary.)


Section D β€” Higher Order Thinking (HOTS) Questions (4–5 Marks Each)

  1. A triangle has two equal angles and the third angle is 96∘96^\circ.
     Find each of the equal angles and name the triangle.

  2. The sum of the interior angles of an nn-sided polygon is 1440∘1440^\circ.
     Find the value of nn.

  3. Draw a circle of radius 4 cm, mark points:
     (a) Inside the circle
     (b) On the circle
     (c) Outside the circle

  4. A quadrilateral has three angles measuring 110∘,95∘,70∘110^\circ, 95^\circ, 70^\circ. Find the fourth angle and classify the quadrilateral.

  5. A line segment AB=8Β cmAB = 8 \text{ cm} is bisected at MM.
     Find AMAM and MBMB, and justify your answer using geometric reasoning.


Section E β€” Multiple Choice Questions (MCQs)

(For Quick Revision)

  1. The total number of right angles in a rectangle is:
     A. 1 B. 2 C. 3 D. 4

  2. The angle formed by two perpendicular lines is:
     A. Acute B. Right C. Obtuse D. Straight

  3. The sum of all angles in a triangle is:Β 
     A. 90∘90^\circ B. 180∘180^\circ C. 270∘270^\circ D. 360∘360^\circ

  4. A line segment joining the centre of a circle to a point on its circumference is called:
     A. Chord B. Diameter C. Radius D. Tangent

  5. Which of the following statements is false?
     A. Every square is a rectangle.
     B. Every rectangle is a square.
     C. Every square is a rhombus.
     D. Every rhombus is a parallelogram.

Worksheet Hints, Solutions & Answers


Section A – Very Short Answer (1 Mark Each)

Q1. Define a point and a line.

Hint: Recall definitions from basic geometry.
Solution:

  • A point has position but no size.

  • A line extends endlessly in both directions, made of infinite points.
    Answer: Point – no dimensions; Line – extends infinitely both ways.


Q2. How many endpoints does a line segment have?

Hint: Think of a line with fixed ends.
Solution: A line segment has two endpoints.
Answer: 2 endpoints.


Q3. Measure of a straight angle?

Hint: It lies on a straight line.
Solution: 180∘180^\circ.
Answer: 180∘180^\circ


Q4. Instrument to draw circles?

Hint: Used with pencil and pin.
Answer: Compass.


Q5. Sum of all angles around a point?

Solution:

Sum of all angles around a point=360∘\text{Sum of all angles around a point} = 360^\circ

Answer: 360∘360^\circ


Q6. Vertices of a triangle?

Answer: 3 vertices.


Q7. Sum of angles of a quadrilateral?

Solution:

Sum=360∘\text{Sum} = 360^\circ

Answer: 360∘360^\circ


Q8. Type of angle greater than 180Β° but less than 360Β°?

Answer: Reflex angle.


Q9. Relationship between radius (r) and diameter (d)?

d=2rd = 2rAnswer: Diameter = 2 Γ— Radius.

Q10. Example of circle shape?

Answer: Clock, coin, wheel.


Section B – Short Answer (2 Marks Each)

Q11. Draw and name: line segment, ray, line.

Hint: Use ruler and pencil.
Solution:

  • ABβ€Ύ\overline{AB} β†’ line segment

  • ABβ†’\overrightarrow{AB} β†’ ray

  • AB↔\overleftrightarrow{AB} β†’ line
    Answer: As shown by symbols above.


Q12. Triangle with angles 90Β° and 45Β° β†’ find third.

Solution:

Sum=180βˆ˜β‡’90+45+x=180β‡’x=45

Answer: Third angle = 45∘45^\circ.


Q13. Two angles sum 130Β° β†’ find supplementary angles.

Hint: Supplementary β‡’ sum 180Β°.
Solution:

180βˆ’130=50180 – 130 = 50

Answer: 50∘50^\circ.


Q14. Quadrilateral angles 80Β°, 90Β°, 75Β° β†’ fourth?

80+90+75+x=360

β‡’x=11580 + 90 + 75 + x = 360 \Rightarrow x = 115Answer: Fourth angle = 115∘115^\circ.


Q15. Circle radius 7 cm β†’ circumference.

C=2Ο€r=2Γ—227Γ—7=44C = 2\pi r = 2 \times \frac{22}{7} \times 7 = 44Answer: C=44Β cmC = 44\ \text{cm}.


Section C – Application (3 Marks Each)

Q16. Prove: Adjacent angles on a straight line = 180Β°.

Hint: Angles on straight line form linear pair.
Solution:
Let ∠1 + ∠2 form straight line.
By linear-pair axiom:

∠1+∠2=180∘\angle1 + \angle2 = 180^\circ

Answer: Hence proved.


Q17. Triangle sides 6 cm, 8 cm, 10 cm β†’ right triangle?

62+82=36+64=100=1026^2 + 8^2 = 36 + 64 = 100 = 10^2

Answer: Yes, right-angled at side 6 and 8 cm.


Q18. Circle diameter 14 cm β†’ radius, C, A.

r=7,C=2Ο€r=44,A=Ο€r2=227Γ—7Γ—7=154r = 7,\quad C = 2\pi r = 44,\quad A = \pi r^2 = \frac{22}{7}\times7\times7 = 154Answer: Radius 7 cm, Circumference 44 cm, Area 154 cmΒ².


Q19. Exterior angle 120Β°, interior opposite 40Β° β†’ other?

120=40+x⇒x=80120 = 40 + x \Rightarrow x = 80

Answer: 80∘80^\circ.

Q20. In parallelogram ABCD, ∠A = 70Β° β†’ others?

∠A=∠C=70,∠B=∠D=110\angle A = \angle C = 70,\quad \angle B = \angle D = 110

Answer: 70Β°, 110Β°, 70Β°, 110Β°.


Section D – HOTS (4–5 Marks Each)

Q21. Two equal angles, third 96Β°.

x+x+96=180β‡’2x=84β‡’x=42x + x + 96 = 180 \Rightarrow 2x = 84 \Rightarrow x = 42

Answer: Equal angles = 42Β° each; Isosceles triangle.


Q22. Sum of interior angles = 1440Β°.

Formula β†’ (nβˆ’2)Γ—180=1440(n-2) Γ— 180 = 1440

nβˆ’2=8β‡’n=10n-2 = 8 \Rightarrow n = 10

Answer: 10-sided polygon (decagon).


Q23. Circle radius 4 cm β†’ mark points.

Hint: Use compass radius 4 cm.
Answer: One inside, one on, one outside β€” as constructed.


Q24. Quadrilateral angles 110Β°, 95Β°, 70Β° β†’ fourth?

110+95+70+x=360β‡’x=85110 + 95 + 70 + x = 360 \Rightarrow x = 85

Answer: Fourth angle = 85Β°; Irregular quadrilateral.


Q25. AB=8AB = 8 cm bisected at M.AM=MB=82=4AM = MB = \frac{8}{2} = 4

Answer: AM = MB = 4 cm; M is midpoint.


Section E – MCQs

No.QuestionAnswer
26Right angles in rectangleD – 4
27Angle between perpendicular linesB – Right angle
28Sum of triangle anglesB – 180Β°
29Centre to circumference lineC – Radius
30False statementB – Every rectangle is a square

Bonus Challenge – Clock Problem

At 3:00 the clock hands are at a right angle (90Β°). Find the next time between 3:00 and 4:00 when they again form a 90Β° angle.


1) Write angles of hour and minute hands (in degrees) at time 3:t3{:}t minutes

  • Hour hand: at 3:00 it is at 90∘90^\circ. It moves 0.5∘0.5^\circ per minute, so at tt minutes past 3:

HourΒ angle=90+0.5t\text{Hour angle} = 90 + 0.5t

  • Minute hand: moves 6∘6^\circper minute, so at tt minutes:

MinuteΒ angle=6t\text{Minute angle} = 6t

2) Angle between the hands

The (smaller) angle between them is the absolute difference:

Angle=∣6tβˆ’(90+0.5t)∣=∣112tβˆ’90∣\text{Angle} = \big|6t – (90 + 0.5t)\big| = \left|\frac{11}{2}t – 90\right|(we used 6tβˆ’0.5t=5.5t=112t6t – 0.5t = 5.5t = \tfrac{11}{2}t).

3) Set the angle equal to 90∘90^\circ and solve

We need

∣112tβˆ’90∣=90.\left|\frac{11}{2}t – 90\right| = 90.

This gives two cases.

Case A: 112tβˆ’90=90\dfrac{11}{2}t – 90 = 90

  • Add 9090Β to both sides:

    112t=180.\dfrac{11}{2}t = 180.

  • Multiply both sides by 22:

    11t=360.11t = 360.

  • Divide by 1111. Do the division digit-by-digit:

    t=36011.t = \frac{360}{11}.

    Long division: 1111 goes into 360360 exactly 3232 times (because 11Γ—32=35211\times32=352), remainder 360βˆ’352=8360-352=8.
    So

    t=32β€…β€Š811Β minutes.

  • Convert the fractional minute 811\dfrac{8}{11} to seconds:

    811Γ—60=48011Β seconds.\frac{8}{11}\times 60 = \frac{480}{11}\ \text{seconds}.

    Divide 480480 by 1111 : 11Γ—43=47311\times43=473, remainder 480βˆ’473=7480-473=7.
    So 48011=43β€…β€Š711\dfrac{480}{11}=43\;\frac{7}{11} seconds.

    Therefore

    t=32Β minutesβ€…β€Š43β€…β€Š711Β seconds.t = 32\ \text{minutes}\;43\;\frac{7}{11}\ \text{seconds}.

    As a decimal, 711\dfrac{7}{11} second β‰ˆ0.63636\approx 0.63636 s, so

    tβ‰ˆ32Β minutesΒ 43.636Β seconds.

Case B: 112tβˆ’90=βˆ’90\dfrac{11}{2}t – 90 = -90

  • Add 9090 to both sides:

    112t=0β‡’t=0.

This is the starting time 3:003{:}00 (the initial right angle).

We want the next time after 3:00, so we take the positive solution from Case A.


Final answer (exact and approximate)

  • Exact: t=36011t = \dfrac{360}{11} minutes after 3:00, i.e. 3:32 ⁣: ⁣43Β 7113{:}32\!:\!43\ \dfrac{7}{11} seconds.

  • Approximate: 3:32:43.636… (3 hours, 32 minutes, 43.636 seconds).

So the hands next form a right angle at about 3:32:43.64.


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